Answer:
Function is [tex]f(x)=1500(0.97)^x[/tex], where a= 1500 and b= 0.97
Step-by-step explanation:
We are given that,
The current bone density of the patient, a = 1500 kg per mg³
The rate of decrease in the bone density, r = 3% = 0.03
Since, the exponential decay is given by [tex]f(x)=ab^x=a(1-r)^x[/tex].
So, the function representing the bone density after x years is,
[tex]f(x)=1500(1-0.03)^x[/tex]
i.e. [tex]f(x)=1500(0.97)^x[/tex]
Thus, the value of a= 1500 and b= 0.97.
Hence, the function representing the bone density is [tex]f(x)=1500(0.97)^x[/tex].