danceluva311
danceluva311
02-03-2017
Mathematics
contestada
Solve: 7+15e^(1-3x)=10
Respuesta :
chul
chul
02-03-2017
So I am going to assume this is a logic problem.
15(2.718282[tex] ^{−3x+1} [/tex]) + 7 = 10
Subtract 7 from both sides.
15(2.718282[tex] ^{−3x+1} [/tex]) = 3
Divide both sides by 15.
[tex] \frac{15(2.72.718282 ^{−3x+1}}{15} = \frac{3}{15} [/tex]
2.718282[tex] ^{-3x+1} [/tex] = [tex] \frac{1}{5} [/tex]
Now you solve for the exponent.
(Take log of both sides)
(
−
3x
+1
)
*
(
log
(2.718282)
)
=
log(1/5)
−
3x
+1 =
[tex] \frac{log \frac{1}{5} }{log(2.718282) } [/tex]
−
3x
+1
=
−
1.609438
−
3x
+1
−1
=
−1.609438
−1
(Subtract 1 from both sides)
−
3x
=
−
2.609438 (divide 3 on both sides)
Answer:
x =
0.869813
or...
Rounded Answer:
0.87
Answer Link
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