Respuesta :

apologiabiology
take the deritiivive
[tex]ln(2)cos(x)2^{sin(x)}-ln(2)sin(x)2^{cos(x)}[/tex]
it is zero at pi/4 and it repeats at every pi
minimum at where slope goesfrom negative to positive
so at 5pi/4 and 13pi/4 so at every 2pi interval


evaluate origial at 5pi/4
[tex]2^{sin(5pi/4)}+2^{cos(5pi/4)}[/tex]=
[tex](2^ \frac{- \sqrt{2} }{2} )+(2^ \frac{- \sqrt{2} }{2} )[/tex]=
[tex]2(2^ \frac{- \sqrt{2} }{2} )[/tex] or aprox 1.22509

Otras preguntas