If a ping pong ball falls from the top of a building that is 168 feet high , how many seconds will it take the ball to hit the ground ? The formula for distance is d=16t^2
here given 'd' that is distance is 168 feet. we need to find seconds that is 't'. from the given formula, ⇒ d=16 t² ⇒ [tex] \frac{d}{16} [/tex] = t² ⇒ t²= [tex] \frac{168}{16} [/tex] ⇒ t²= 10.5 ⇒ t=[tex] \sqrt{10.5} [/tex] ⇒ t=3.24 thus the seconds required is 3.24 seconds
